Unit of equilibrium constant for the given reaction is Ni ( s )+4 CO ( g ) leftharpoons Ni ( CO )4( g )

Question

Unit of equilibrium constant for the given reaction is Ni ( s )+4 CO ( g ) leftharpoons Ni ( CO )4( g ) (A) ( mol / L )-3 (B) ( mol / L )3 (C) ( mol / L )-4 (D) ( mol / L )4

Tardigrade Admin · Accepted Answer

K=([ Ni ( CO )4]/[ CO ]4)=( mol L -1/( mol L -1)4)=( mol l -1)-3

Q. Unit of equilibrium constant for the given reaction is $N i (s) + 4 CO (g) ⇌ N i (CO)_{4} (g)$

$(m o l / L)^{- 3}$

$(m o l / L)^{3}$

$(m o l / L)^{- 4}$

$(m o l / L)^{4}$

$K = \frac{[ N i ( CO ) _{4} ]}{[ CO ] ^{4}} = \frac{m o l L ^{- 1}}{( m o l L ^{- 1} ) ^{4}} = (m o l l^{- 1})^{- 3}$

Q. Unit of equilibrium constant for the given reaction is Ni(s)+4CO(g)⇌Ni(CO)4​(g)

(mol/L)−3

(mol/L)3

(mol/L)−4

(mol/L)4