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Tardigrade
Question
Mathematics
|24 25 26 25 26 27 26 27 27| is equal to
Q.
∣
∣
24
25
26
25
26
27
26
27
27
∣
∣
is equal to
1804
214
EAMCET
EAMCET 2011
Report Error
A
0
B
-1
C
1
D
2
Solution:
Let
Δ
∣
∣
24
25
26
25
26
27
26
27
27
∣
∣
Applying
R
2
→
R
2
−
R
1
and
R
3
→
R
3
−
R
2
Δ
=
∣
∣
24
1
1
25
1
1
26
1
0
∣
∣
=
1
[
25
−
26
]
−
1
[
24
−
26
]
=
−
1
+
2
=
1