Question

${}_{92}^{238}U$ emits $8$ (\alpha-particles and $6$ ( $\beta$ -particles. The neutron proton ratio in the product nucleus is

• A. 60/41
• B. 61/40
• C. 62/41
• D. 61/42

Answer 1

Answer: (C)

${}_{92}{U}^{238}\stackrel{-8\alpha }{\to }{}_{76}{X}^{206}\stackrel{-6\beta }{\to }{}_{82}{Y}^{206}$
In $Y$, number of protons$=82$
number of neutrons =mass number - number of proton
$=206-82$
$=124$
$\frac{n}{p}=\frac{124}{82}=\frac{62}{41}$