200 text cm3 of an aqueous solution of a protein contains 1.26 g. of protein. The O.P. of such a solution at 300 K is found to be 2.57× 10-3 atm. Molar mass of protein is

Question

200 text cm3 of an aqueous solution of a protein contains 1.26 g. of protein. The O.P. of such a solution at 300 K is found to be 2.57× 10-3 atm. Molar mass of protein is (A)  60287 text g.mol-1  (B)  30242. text g.mol-1  (C)  40404 text g. text mol-1  (D)  50404 text g. text mol-1

Tardigrade Admin · Accepted Answer

: Osmotic pressure =(n/V)RT 2.57× 10-3=(1.26/M× 200)× 1000× 0.0821× 300 M=60377.0 text gmol-1 .

Q. $200 c m^{3}$ of an aqueous solution of a protein contains 1.26 g. of protein. The O.P. of such a solution at 300 K is found to be $2.57 \times 10^{- 3}$ atm. Molar mass of protein is

$60287 g . m o l^{- 1}$

$30242. g . m o l^{- 1}$

$40404 g . m o l^{- 1}$

$50404 g . m o l^{- 1}$

: Osmotic pressure $= \frac{n}{V} RT$ $2.57 \times 10^{- 3} = \frac{1.26}{M \times 200} \times 1000 \times 0.0821 \times 300$ $M = 60377.0 g m o l^{- 1}$ .

Q. 200cm3 of an aqueous solution of a protein contains 1.26 g. of protein. The O.P. of such a solution at 300 K is found to be 2.57×10−3 atm. Molar mass of protein is

60287g.mol−1

30242.g.mol−1

40404g.mol−1

50404g.mol−1