20 ml of N/10 HCl, 30 ml of N/15 HNO3 and 40 ml of N H2SO4 are mixed. What will be normality of the resulting solution ?

Question

20 ml of N/10 HCl, 30 ml of N/15 HNO3 and 40 ml of N H2SO4 are mixed. What will be normality of the resulting solution ? (A) 44/90 (B) 90/44 (C) 22/90 (D) 90/95

Tardigrade Admin · Accepted Answer

As we know from the law of equivalence that N1V1+N2V2+N3V3=NRVR 20× (1/10)+30× (1/15)+40×1 =NR×90 NR=(44/90)

Q. $20 m l$ of $N /10 H Cl$ , $30 m l$ of $N /15 H N O_{3}$ and $40 m l$ of $N H_{2} S O_{4}$ are mixed. What will be normality of the resulting solution ?

$44/90$

$90/44$

$22/90$

$90/95$

As we know from the law of equivalence that
$N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3} = N_{R} V_{R}$
$20 \times \frac{1}{10} + 30 \times \frac{1}{15} + 40 \times 1$
$= N_{R} \times 90$
$N_{R} = \frac{44}{90}$

Q. 20ml of N/10HCl, 30ml of N/15HNO3​ and 40ml of NH2​SO4​ are mixed. What will be normality of the resulting solution ?

44/90

90/44

22/90

90/95