20mL of 0⋅5NHCl=20×0⋅5 millieq. =10 milli eq a of HCl 35mL of 0⋅1NNaOH=35×0⋅1 milli eq. =3⋅5 milli eq ⋅ of NaOH.
Thus, 3⋅5 milli eq a of NaOH will neutralize 3⋅5 milli eq ⋅ of HCl(10−3⋅5)=6⋅5millieq⋅ of HCl will be left.
Therefore, solution will be acidic and it will turn methyl orange red.