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  4. 20 mL of 0 ⋅ 5 NHCl and 35 mL of 0 ⋅ 1 N NaOH are mixed. The resulting solution will

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Q. $20 \,mL$ of $0 \cdot 5 \,NHCl$ and $35 \, mL$ of $0 \cdot \,1 \,N \, NaOH$ are mixed. The resulting solution will

JIPMERJIPMER 2013Some Basic Concepts of Chemistry

Solution:

$20\, mL$ of $0 \cdot 5 \,N \,HCl =20 \times 0 \cdot 5$ millieq.
$=10$ milli eq a of $HCl$
$35\, mL$ of $0 \cdot 1 N NaOH =35 \times 0 \cdot 1$ milli eq. $=3 \cdot 5$ milli eq $\cdot$ of $NaOH$.
Thus, $3 \cdot 5$ milli eq a of $NaOH$ will neutralize
$3 \cdot 5$ milli eq $\cdot$ of $HCl (10-3 \cdot 5)=6 \cdot 5 milli eq \cdot$ of $HCl$ will be left.
Therefore, solution will be acidic and it will turn methyl orange red.