20 ampere current is flowing in a long straight wire. The intensity of magnetic field at a distance 10 cm from the wire will be

Question

20 ampere current is flowing in a long straight wire. The intensity of magnetic field at a distance 10 cm from the wire will be (A) 2 × 10-5 Wb / m 2 (B) 9 × 10-5 Wb / m 2 (C) 4 × 10-5 Wb / m 2 (D) 6 × 10-5 Wb / m 2

Tardigrade Admin · Accepted Answer

Here: i=20 A, r=10 cm =01 m Intensity of magnetic field produced due to straight current carrying wire is B =(μ0/4 π) × (2 i/r) =10-7 × (2 × 20/0.1) =4 × 10-5 Wb / m 2

Q. $20$ ampere current is flowing in a long straight wire. The intensity of magnetic field at a distance $10 c m$ from the wire will be

$2 \times 1 0^{- 5} Wb / m^{2}$

$9 \times 1 0^{- 5} Wb / m^{2}$

$4 \times 1 0^{- 5} Wb / m^{2}$

$6 \times 1 0^{- 5} Wb / m^{2}$

Here: $i = 20 A, r = 10 c m = 01 m$
Intensity of magnetic field produced due to straight current carrying wire is
$B = \frac{μ _{0}}{4 π} \times \frac{2 i}{r}$
$= 1 0^{- 7} \times \frac{2 \times 20}{0.1}$
$= 4 \times 1 0^{- 5} Wb / m^{2}$

Q. 20 ampere current is flowing in a long straight wire. The intensity of magnetic field at a distance 10cm from the wire will be

2×10−5Wb/m2

9×10−5Wb/m2

4×10−5Wb/m2

6×10−5Wb/m2