Tardigrade
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Tardigrade
Question
Chemistry
20.0kg of N2(g) and 3.0kg of H2(g) are mixed to produce (NH)3(.g.) . The amount of (NH)3(g) formed is :
Q.
20.0
k
g
of
N
2
(
g
)
and
3.0
k
g
of
H
2
(
g
)
are mixed to produce
(
N
H
)
3
(
g
)
. The amount of
(
N
H
)
3
(
g
)
formed is :
218
177
NTA Abhyas
NTA Abhyas 2020
Report Error
A
17
k
g
B
34
k
g
C
20
k
g
D
3
k
g
Solution:
28
g
N
2
+
6
g
3
H
2
→
34
g
2
N
H
3
Limiting reactant is
H
2
.
Weight of
N
H
3
obtained from
6
×
1
0
−
3
k
g
of
H
2
=
34
×
1
0
−
3
k
g
∴
Weight of
N
H
3
obtained from
3
k
g
of
H
2
=
6
×
1
0
−
3
34
×
1
0
−
3
×
3
=
17
k
g
N
H
3