2 NOCl ( g ) leftharpoons 2 NO ( g )+ Cl 2( g ) In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol / L. The equilibrium constant at 30° C is × 10-4.

Question

2 NOCl ( g ) leftharpoons 2 NO ( g )+ Cl 2( g ) In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol / L. The equilibrium constant at 30° C is × 10-4. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/e171ea8d28a77f0180830607d26bce41-.png" /> ∵ x =0.4 M ∴[ NOCl ] eq =1.6 M [ NO ] eq =0.4 M [ Cl 2] eq =0.2 M ⇒ K c =([ NO ]2[ Cl 2]/[ NOCl ]2)=([0.4]2[0.2]/[1.6]2) K c =(32/2.56) × 10-3 K c =12.5 × 10-3 K c =125 × 10-4 Integer answer is 125

Q. 2NOCl(g)⇌2NO(g)+Cl2​(g) In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4mol/L. The equilibrium constant at 30∘C is _______ ×10−4.

∵x=0.4M ∴[NOCl]eq​=1.6M [NO]eq​=0.4M [Cl2​]eq​=0.2M ⇒Kc​=[NOCl]2[NO]2[Cl2​]​=[1.6]2[0.4]2[0.2]​ Kc​=2.5632​×10−3 Kc​=12.5×10−3 Kc​=125×10−4 Integer answer is 125

Q. $2 NOCl (g) ⇌ 2 NO (g) + C l_{2} (g)$
In an experiment, $2.0$ moles of $NOCl$ was placed in a one-litre flask and the concentration of $NO$ after equilibrium established, was found to be $0.4 m o l / L$ . The equilibrium constant at $3 0^{\circ} C$ is _______ $\times 1 0^{- 4}$ .