2 moles of helium gas is mixed with 3 moles of hydrogen molecules (taken to be rigid). Find the molar specific heat of the mixture at constant volume. (.R=8.3J/molK.)

Question

2 moles of helium gas is mixed with 3 moles of hydrogen molecules (taken to be rigid). Find the molar specific heat of the mixture at constant volume. (.R=8.3J/molK.) (A) 15.7J/molK (B) 21.6J/molK (C) 19.7J/molK (D) 17.4J/molK

Tardigrade Admin · Accepted Answer

(n1 Cv1 + n2 Cv2/n1 + n2)=(2 × (3/2) R + 3 × (5/2) R/2 + 3)=(3 R + 15 (R/2)/5)=((2 R/10))=(21 × 8 . 3/10)=17.4JmolK

Q. $2$ moles of helium gas is mixed with $3$ moles of hydrogen molecules (taken to be rigid). Find the molar specific heat of the mixture at constant volume. $(R = 8.3 J / m o l K)$

$15.7 J / m o l K$

$21.6 J / m o l K$

$19.7 J / m o l K$

$17.4 J / m o l K$

$\frac{n _{1} C _{v_{1}} + n _{2} C _{v_{2}}}{n _{1} + n _{2}} = \frac{2 \times \frac{3}{2} R + 3 \times \frac{5}{2} R}{2 + 3} = \frac{3 R + 15 \frac{R}{2}}{5} = (\frac{2 R}{10}) = \frac{21 \times 8.3}{10} = 17.4 J_{m o l} K$

Q. 2 moles of helium gas is mixed with 3 moles of hydrogen molecules (taken to be rigid). Find the molar specific heat of the mixture at constant volume. (R=8.3J/molK)

15.7J/molK

21.6J/molK

19.7J/molK

17.4J/molK