2 g of a non-volatile, non-electrolyte solute is dissolved in 100 g of two different solvents X and Y whose Kb values are in the ratio of 1: 4. The value of ((Δ T b ( X )/Δ T b ( Y ))) is

Question

2 g of a non-volatile, non-electrolyte solute is dissolved in 100 g of two different solvents X and Y whose Kb values are in the ratio of 1: 4. The value of ((Δ T b ( X )/Δ T b ( Y ))) is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ T b = K b × m ∴ (Δ T b ( X )/Δ T b ( Y ))=( K b ( X ) × m / K b ( Y ) × m ) =( K b ( X )/ K b ( Y ))=(1/4)=0.25

Q. $2 g$ of a non-volatile, non-electrolyte solute is dissolved in $100 g$ of two different solvents $X$ and $Y$ whose $K_{b}$ values are in the ratio of $1 : 4$ . The value of $(\frac{Δ T _{b} ( X )}{Δ T _{b} ( Y )})$ is_________

$Δ T_{b} = K_{b} \times m$
$∴ \frac{Δ T _{b} ( X )}{Δ T _{b} ( Y )} = \frac{K _{b} ( X ) \times m}{K _{b} ( Y ) \times m}$
$= \frac{K _{b} ( X )}{K _{b} ( Y )} = \frac{1}{4} = 0.25$

Q. 2g of a non-volatile, non-electrolyte solute is dissolved in 100g of two different solvents X and Y whose Kb​ values are in the ratio of 1:4. The value of (ΔTb​(Y)ΔTb​(X)​) is_________

ΔTb​=Kb​×m ∴ΔTb​(Y)ΔTb​(X)​=Kb​(Y)×mKb​(X)×m​ =Kb​(Y)Kb​(X)​=41​=0.25

Q. $2 g$ of a non-volatile, non-electrolyte solute is dissolved in $100 g$ of two different solvents $X$ and $Y$ whose $K_{b}$ values are in the ratio of $1 : 4$ . The value of $(\frac{Δ T _{b} ( X )}{Δ T _{b} ( Y )})$ is_________

$Δ T_{b} = K_{b} \times m$
$∴ \frac{Δ T _{b} ( X )}{Δ T _{b} ( Y )} = \frac{K _{b} ( X ) \times m}{K _{b} ( Y ) \times m}$
$= \frac{K _{b} ( X )}{K _{b} ( Y )} = \frac{1}{4} = 0.25$