Question

$2\, g$ of a non-volatile, non-electrolyte solute is dissolved in $100\, g$ of two different solvents $X$ and $Y$ whose $K_{b}$ values are in the ratio of $1: 4$. The value of $\left(\frac{\Delta T _{ b }( X )}{\Delta T _{ b }( Y )}\right)$ is_________

Answer 1

$\Delta T _{ b }= K _{ b } \times m$
$\therefore \frac{\Delta T _{ b }( X )}{\Delta T _{ b }( Y )}=\frac{ K _{ b }( X ) \times m }{ K _{ b }( Y ) \times m }$
$=\frac{ K _{ b }( X )}{ K _{ b }( Y )}=\frac{1}{4}=0.25$