2.76 g of silver carbonate on being strongly heated yields a residue weighing (in gram) (At. wt.: Ag =108, C =12, O=16)

Question

2.76 g of silver carbonate on being strongly heated yields a residue weighing (in gram) (At. wt.: Ag =108, C =12, O=16) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Ag 2 CO 3 xrightarrowΔ 2 Ag + CO 2+(1/2) O 2 moles of Ag 2 CO 3=(2.76/276)=0.01 moles of Ag produced =0.02 moles mass of Ag produced =0.02 × 108=2.16 gm

Q. $2.76 g$ of silver carbonate on being strongly heated yields a residue weighing (in gram) (At. wt.: $A g = 108, C = 12$ , $O = 16)$

$A g_{2} C O_{3} Δ 2 A g + C O_{2} + \frac{1}{2} O_{2}$
moles of $A g_{2} C O_{3} = \frac{2.76}{276} = 0.01$
moles of $A g$ produced $= 0.02$ moles
mass of $A g$ produced $= 0.02 \times 108 = 2.16 g m$

Q. 2.76g of silver carbonate on being strongly heated yields a residue weighing (in gram) (At. wt.: Ag=108,C=12, O=16)

Ag2​CO3​Δ​2Ag+CO2​+21​O2​ moles of Ag2​CO3​=2762.76​=0.01 moles of Ag produced =0.02 moles mass of Ag produced =0.02×108=2.16gm

Q. $2.76 g$ of silver carbonate on being strongly heated yields a residue weighing (in gram) (At. wt.: $A g = 108, C = 12$ , $O = 16)$

$A g_{2} C O_{3} Δ 2 A g + C O_{2} + \frac{1}{2} O_{2}$
moles of $A g_{2} C O_{3} = \frac{2.76}{276} = 0.01$
moles of $A g$ produced $= 0.02$ moles
mass of $A g$ produced $= 0.02 \times 108 = 2.16 g m$