2.6g mixture of carbonates of magnesium ( MgCO3 ) and calcium ( CaCO3 ) is strongly heated to the constant weight of 1.3g . The weight of calcium carbonate in the original mixture?

Question

2.6g mixture of carbonates of magnesium ( MgCO3 ) and calcium ( CaCO3 ) is strongly heated to the constant weight of 1.3g . The weight of calcium carbonate in the original mixture? (A) 980mg (B) 400mg (C) 1.75g (D) 0.74g

Tardigrade Admin · Accepted Answer

Suppose weight of CaCO3=xg. Then (MgCO)3=(.2.6-x.)g CaCO3 arrow underset100 g arrow CaO+CO2⇒ xg arrow 0.56xg underset84 gMg (CO)3 arrow underset40 gMgO + (CO)2⇒ (.2.6-x.)g arrow (40/84)(.2.6-x.)g 0.56x+(40/84)(.2.6-x.)=1.3 (Given) 47.04x+104-40x=109.2⇒ 7.04x=5.2 text or x=0.74g

Q. $2.6 g$ mixture of carbonates of magnesium ( $M g C O_{3}$ ) and calcium ( $C a C O_{3}$ ) is strongly heated to the constant weight of $1.3 g$ . The weight of calcium carbonate in the original mixture?

$980 m g$

$400 m g$

$1.75 g$

$0.74 g$

Q. 2.6g mixture of carbonates of magnesium ( MgCO3​ ) and calcium ( CaCO3​ ) is strongly heated to the constant weight of 1.3g . The weight of calcium carbonate in the original mixture?

980mg

400mg

1.75g

0.74g

Suppose weight of CaCO3​=xg. Then (MgCO)3​=(2.6−x)g CaCO3​→100g→​CaO+CO2​⇒xg→0.56xg 84gMg(CO)3​​→40gMgO+(CO)2​​⇒(2.6−x)g→8440​(2.6−x)g 0.56x+8440​(2.6−x)=1.3 (Given) 47.04x+104−40x=109.2⇒7.04x=5.2 or x=0.74g

Q. $2.6 g$ mixture of carbonates of magnesium ( $M g C O_{3}$ ) and calcium ( $C a C O_{3}$ ) is strongly heated to the constant weight of $1.3 g$ . The weight of calcium carbonate in the original mixture?

$980 m g$

$400 m g$

$1.75 g$

$0.74 g$