Question

$2.5c{m}^3$ of $0.2M{H}_{2}S{O}_4$ solution is diluted to $0.5d{m}^3$ . Find normality of the diluted solution.

• A. $0.2N$
• B. $0.02N$
• C. $0.002N$
• D. $0.04N$

Answer 1

Answer: (C)

Given,

volume of $H_{2}S{O}_4$ before dilution, $V_1=2.5c{m}^3$

$=2.5\times 10^{-3}d{m}^3$

volume of $H_{2}S{O}_4$ after dilution, $V_2=0.5d{m}^3$

Concentration of $H_{2}S{O}_4$ before dilution $=0.2M$

$=0.4N[\because 1N=2M]$

Concentration (normality) of $H_{2}S{O}_4$ after dilution, $N_2=$ ?

Normality equation is

$\underset{\text{(before dilution) }}{N_1{V}_1}=\underset{\text{(after dilution) }}{N_2{V}_2}$

$2.5\times 10^{-3}\times 0.4=N_2\times 0.5$

$\therefore N_2=\frac{2.5\times 10^{-3}\times 0.4}{0.5}$

$=2\times 10^{-3}=0.002N$