1M N H4OH and 1M HCl are mixed to make a total volume of 300 mL . If pH of the mixture is 9.26 and pKa(N H4+)=9.26 then what would be the volume ratio of N H4OH and HCl .

Question

1M N H4OH and 1M HCl are mixed to make a total volume of 300 mL . If pH of the mixture is 9.26 and pKa(N H4+)=9.26 then what would be the volume ratio of N H4OH and HCl . (A) 2:1 (B) 1:2 (C) 2:3 (D) 3:2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-oollw1vhtveang7p.jpg" /> pOH =14- pH = pK b + log ( x /300-2 x ) =14-9.26=- log (10-4.74)+ log ( x /300-2 x ) ⇒ (x/300 - 2 x)=1 ⇒ 300=3x⇒ x=100 mL ( textV textNH text4 textOH/ textV textHCl) text= text2

Q. $1 M N H_{4} O H$ and $1 M H Cl$ are mixed to make a total volume of $300 m L$ . If $p H$ of the mixture is $9.26$ and $p K_{a} (N H_{4}^{+}) = 9.26$ then what would be the volume ratio of $N H_{4} O H$ and $H Cl$ .

2:1

1:2

2:3

3:2

$pO H = 14 - p H = p K_{b} + lo g \frac{x}{300 - 2 x}$
$= 14 - 9.26 = - lo g (1 0^{- 4.74}) + lo g \frac{x}{300 - 2 x}$
$\Rightarrow \frac{x}{300 - 2 x} = 1$
$\Rightarrow 300 = 3 x \Rightarrow x = 100 m L$
$\frac{V _{NH_{4} OH}}{V _{HCl}} = 2$

Q. 1MNH4​OH and 1MHCl are mixed to make a total volume of 300mL . If pH of the mixture is 9.26 and pKa​(NH4+​)=9.26 then what would be the volume ratio of NH4​OH and HCl .

2:1

1:2

2:3

3:2

pOH=14−pH=pKb​+log300−2xx​ =14−9.26=−log(10−4.74)+log300−2xx​ ⇒300−2xx​=1 ⇒300=3x⇒x=100mL VHCl​VNH4​OH​​=2

Q. $1 M N H_{4} O H$ and $1 M H Cl$ are mixed to make a total volume of $300 m L$ . If $p H$ of the mixture is $9.26$ and $p K_{a} (N H_{4}^{+}) = 9.26$ then what would be the volume ratio of $N H_{4} O H$ and $H Cl$ .

$pO H = 14 - p H = p K_{b} + lo g \frac{x}{300 - 2 x}$
$= 14 - 9.26 = - lo g (1 0^{- 4.74}) + lo g \frac{x}{300 - 2 x}$
$\Rightarrow \frac{x}{300 - 2 x} = 1$
$\Rightarrow 300 = 3 x \Rightarrow x = 100 m L$
$\frac{V _{NH_{4} OH}}{V _{HCl}} = 2$