1g of a complex [.Cr(. H2 O .)5Cl].(Cl)2⋅ H2O ( molecularweight266.5u ) was passed through a cation exchanger to produce HCl . The acid liberated was diluted to 1litre . The normality of this acid solution is

Question

1g of a complex [.Cr(. H2 O .)5Cl].(Cl)2⋅ H2O ( molecularweight266.5u ) was passed through a cation exchanger to produce HCl . The acid liberated was diluted to 1litre . The normality of this acid solution is (A) 5× 10- 3 N (B) 7.5× 10- 3 N (C) 7.5× 10- 2 N (D) 7.5× 10- 1 N

Tardigrade Admin · Accepted Answer

Mole of complex =(mass/molar mass)=(1/266 .5) one mole of complex produces two moles of HCl .[ Cr ( H 2 O )5 Cl ] Cl 2 arrow Cr ( H 2 O )5 Cl ]2+ 2 Cl - Mole of HCl formed =(1/266.5)× 2 NHCl= (number of moles/Volume of solution)× n-factor= (2/266 . 5) =7.5× 10- 3N

Q. $1 g$ of a complex $[C r (H_{2} O)_{5} Cl] (Cl)_{2} \cdot H_{2} O$ ( $m o l ec u l a r w e i g h t 266.5 u$ ) was passed through a cation exchanger to produce $H Cl$ . The acid liberated was diluted to $1 l i t re$ . The normality of this acid solution is

$5 \times 1 0^{- 3}$ $N$

$7.5 \times 1 0^{- 3}$ $N$

$7.5 \times 1 0^{- 2}$ $N$

$7.5 \times 1 0^{- 1}$ $N$

Q. 1g of a complex [Cr(H2​O)5​Cl](Cl)2​⋅H2​O ( molecularweight266.5u ) was passed through a cation exchanger to produce HCl . The acid liberated was diluted to 1litre . The normality of this acid solution is

5×10−3 N

7.5×10−3 N

7.5×10−2 N

7.5×10−1 N

Mole of complex =molarmassmass​=266.51​ one mole of complex produces two moles of HCl [Cr(H2​O)5​Cl]Cl2​→Cr(H2​O)5​Cl]2+2Cl− Mole of HCl formed =266.51​×2 NHCl​=Volumeofsolutionnumberofmoles​×n−factor=266.52​ =7.5×10−3N

Q. $1 g$ of a complex $[C r (H_{2} O)_{5} Cl] (Cl)_{2} \cdot H_{2} O$ ( $m o l ec u l a r w e i g h t 266.5 u$ ) was passed through a cation exchanger to produce $H Cl$ . The acid liberated was diluted to $1 l i t re$ . The normality of this acid solution is

$5 \times 1 0^{- 3}$ $N$

$7.5 \times 1 0^{- 3}$ $N$

$7.5 \times 1 0^{- 2}$ $N$

$7.5 \times 1 0^{- 1}$ $N$