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Tardigrade
Question
Chemistry
19 g of a mixture containing NaHCO 3 and Na 2 CO 3 on complete heating liberated 1.12 L of CO 2 at STP. The weight of the remaining solid was 15.9 g. What is the weight (in g ) of Na 2 CO 3 in the mixture before heating?
Q.
19
g
of a mixture containing
N
a
H
C
O
3
and
N
a
2
C
O
3
on complete heating liberated
1.12
L
of
C
O
2
at
STP
. The weight of the remaining solid was
15.9
g
. What is the weight (in
g
) of
N
a
2
C
O
3
in the mixture before heating?
2338
223
EAMCET
EAMCET 2011
Report Error
A
8.4
B
15.9
C
4.0
D
10.6
Solution:
Molecular weight of
N
a
H
C
O
3
=
23
+
1
+
12
+
48
=
84
Molecular weight of
N
a
2
C
O
3
=
46
+
12
+
48
=
106
Hence, total weight
=
84
+
106
=
190
∵
In
19
g
of a mixture, weight of
N
a
2
C
O
3
is
=
106
∴
In
19
g
of a mixture weight of
N
a
2
C
O
3
=
190
106
×
19
=
10.6
g