18.72 g of a substance 'X' occupies 1.81 cm3. What will be its density measured in correct significant figures?

Question

18.72 g of a substance 'X' occupies 1.81 cm3. What will be its density measured in correct significant figures? (A) 10.3 g cm3  (B) 10.34 g cm3  (C) 10.4 g cm3  (D) 10.3425 g cm3

Tardigrade Admin · Accepted Answer

Density = ( textMass/ textVolume) = (18.72/1.81) = 1.34 g cm-3 Since volume contains 3 significant figures hence answer will be 10.3 g cm-3

Q. $18.72 g$ of a substance $^{'} X^{'}$ occupies $1.81 c m^{3}$ . What will be its density measured in correct significant figures?

$10.3 g c m^{3}$

$10.34 g c m^{3}$

$10.4 g c m^{3}$

$10.3425 g c m^{3}$

Density $= \frac{Mass}{Volume}$
$= \frac{18.72}{1.81}$
$= 1.34 g c m^{- 3}$
Since volume contains $3$ significant figures hence answer will be $10.3 g c m^{- 3}$

Q. 18.72g of a substance ′X′ occupies 1.81cm3. What will be its density measured in correct significant figures?

10.3gcm3

10.34gcm3

10.4gcm3

10.3425gcm3