Question

$17mg$ of a hydrocarbon (M.F. $C_{10}{H}_{16}$ ) takes up $8.40mL$ of the $H_2$ gas measured at $0^{\circ }C$ and $760mm$ of $Hg$. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is _____

Answer 1

Answer: 3

Moles of hydrocarbon $=\frac{17\times 10^{-3}}{136}=1.25\times 10^{-4}$
Mole of $H_2$ gas
$\Rightarrow 1\times \frac{8.40}{1000}=n\times 0.0821\times 273$
$\Rightarrow n=3.75\times 10^{-4}$
Hydrogen molecule used for 1 molecule of hydrocarbon is 3
$=\frac{3.75\times 10^{-4}}{1.25\times 10^{-4}}=3$