Question

$17 \,mg$ of a hydrocarbon (M.F. $C _{10} H _{16}$ ) takes up $8.40\, mL$ of the $H _2$ gas measured at $0^{\circ} C$ and $760 \,mm$ of $Hg$. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is _____

Answer 1

Moles of hydrocarbon $=\frac{17 \times 10^{-3}}{136}=1.25 \times 10^{-4}$
Mole of $H _2$ gas
$\Rightarrow 1 \times \frac{8.40}{1000}= n \times 0.0821 \times 273$
$ \Rightarrow n =3.75 \times 10^{-4}$
Hydrogen molecule used for 1 molecule of hydrocarbon is 3
$=\frac{3.75 \times 10^{-4}}{1.25 \times 10^{-4}}=3$