Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
12 g of Mg with excess of HCI at NTP gives
Q.
12
g
of
M
g
with excess of
H
C
I
at NTP gives
1849
186
COMEDK
COMEDK 2011
Some Basic Concepts of Chemistry
Report Error
A
11.2
d
m
3
of
H
2
22%
B
22.4
d
m
3
of
H
2
33%
C
5.6
d
m
3
of
H
2
29%
D
15.6
d
m
3
of
H
2
16%
Solution:
M
g
+
2
H
Cl
→
M
g
C
l
2
+
H
2
(
24
g
)
(
2
g
or
22.4
d
m
3
)
Thus,
12
g
of
M
g
produces
1
g
or
11.2
d
m
3
H
2