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  4. 12 g of Mg with excess of HCI at NTP gives

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Q. $12 \,g$ of $Mg$ with excess of $HCI $ at NTP gives

COMEDKCOMEDK 2011Some Basic Concepts of Chemistry

Solution:

$Mg +2 HCl \to MgCl _2+ H _2$
$(24 \,g)\left(2\right. g $ or $\left.22.4 \,d m^3\right)$
Thus, $12 g$ of $Mg$ produces $1 \,g$ or $11.2 \, dm ^3 H _2$