Question

$12g$ of $Mg$ (at. mass $=24$ ) will react completely with an acid to give :

• A. 1 mole of $H_2$
• B. $\frac{1}{2}$ mole of $H_2$
• C. 1 mole $O_2$
• D. None of these

Answer 1

Answer: (B)

$Mg+2HCl⟶MgC{l}_2+H_2$
$24g.Mg$ gives one mole $H_2$