12 g of Mg (at. mass 24) on reacting completely with acid gives hydrogen gas, the volume of which at STP would be

Question

12 g of Mg (at. mass 24) on reacting completely with acid gives hydrogen gas, the volume of which at STP would be (A) 22.4 L (B) 11.2 L (C) 44.8 L (D) 6.1 L

Tardigrade Admin · Accepted Answer

Mg + 2HCI→ MgCL2 + H2 ∵24 g Mg evolves 22.4 L H2 at STP ∴ 12 g Mg evolves H2 at STP(22.4/24)×12 = 11.2 L at STP

Q. $12 g$ of $M g$ (at. mass $24$ ) on reacting completely with acid gives hydrogen gas, the volume of which at STP would be

$22.4 L$

$11.2 L$

$44.8 L$

$6.1 L$

$M g + 2 H C I \to M g C L_{2} + H_{2}$
$∵ 24 g M g$ evolves $22.4 L H_{2}$ at $STP$
$∴ 12 g M g$ evolves $H_{2}$ at $STP \frac{22.4}{24} \times 12 = 11.2 L a t STP$

Q. 12g of Mg (at. mass 24) on reacting completely with acid gives hydrogen gas, the volume of which at STP would be

22.4L

11.2L

44.8L

6.1L