Let R be radius of big drop and r of small drop, then volume of big drop =1000× volume of small drop 34πR3=1000×34πr3 ⇒R=10r
Potential of small drop V=4πε01⋅rq… (i)
Potential of bigger drop V=4πε01R1000q V=4πε01×1000×10rq… (ii)
From Eqs. (i) and (ii), we get V=100V.