100 mL of PH3 when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is - PH3(g) → P(s) + 3/2 H2(g)

Question

100 mL of PH3 when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is - PH3(g) → P(s) + 3/2 H2(g) (A) 50 mL increase (B) 500 mL decrease (C) 900 mL decrease (D) Does not change

Tardigrade Admin · Accepted Answer

underset text2 vol2PH3 → underset text3 vol3H2+2P 2 vol of PH3 give 3 vol of H2 ∴ 100 mL of PH3 gives 150 mL of H2 ∴ Increase in volume =150 mL-100 mL =50 mL

Q. $100 m L$ of $P H_{3}$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is - $P H_{3} (g) P (s) + 3/2 H_{2} (g)$

$50$ mL increase

$500$ mL decrease

$900$ mL decrease

Does not change

$2 vol 2 PH X_{3} \to 3 vol 3 H X_{2} + 2 P$
$2$ vol of $P H_{3}$ give $3$ vol of $H_{2}$
$∴ 100 m L$ of $P H_{3}$ gives $150 m L$ of $H_{2}$
$∴$ Increase in volume $= 150 m L - 100 m L$
$= 50 m L$

Q. 100mL of PH3​ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is - PH3​(g)​P(s)+3/2H2​(g)

50 mL increase

500 mL decrease

900 mL decrease