100 ml of HCl +35 ml of NaOH, colour of methyl orange in the solution will be:

Question

100 ml of HCl +35 ml of NaOH, colour of methyl orange in the solution will be: (A) Red (B) Yellow (C) Can't be predicted (D) Methyl orange is not suitable indicator

Tardigrade Admin · Accepted Answer

When 100 ml HCl is added to 35 mL NaOH , 35 mL HCl is utilized to neutralise NaOH, while 65 mL HCl remains as such. Hence, the solution becomes acidic. In acid solution, the colour of methyl orange (indicator) is red due to the presence of Me + ion as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ca82a56b0ed96755a7e1c9016ebff13c-.png" />

Q. $100 m l$ of $H Cl + 35 m l$ of $N a O H$ , colour of methyl orange in the solution will be:

Red

Yellow

Can't be predicted

Methyl orange is not suitable indicator

When $100 m l H Cl$ is added to $35 m L N a O H, 35 m L$ $H Cl$ is utilized to neutralise $N a O H$ , while $65 m L H Cl$ remains as such. Hence, the solution becomes acidic. In acid solution, the colour of methyl orange (indicator) is red due to the presence of $M e^{+}$ ion as

Q. 100 ml of HCl+35ml of NaOH, colour of methyl orange in the solution will be:

Red

Yellow

Can't be predicted

Methyl orange is not suitable indicator

When 100mlHCl is added to 35mLNaOH,35mL HCl is utilized to neutralise NaOH, while 65mLHCl remains as such. Hence, the solution becomes acidic. In acid solution, the colour of methyl orange (indicator) is red due to the presence of Me+ ion as

Q. $100 m l$ of $H Cl + 35 m l$ of $N a O H$ , colour of methyl orange in the solution will be:

When $100 m l H Cl$ is added to $35 m L N a O H, 35 m L$ $H Cl$ is utilized to neutralise $N a O H$ , while $65 m L H Cl$ remains as such. Hence, the solution becomes acidic. In acid solution, the colour of methyl orange (indicator) is red due to the presence of $M e^{+}$ ion as