100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon?

Question

100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Mass of acetic acid adsorbed by 2 g charcoal = 100 × 10-3 × (0.6 - 0.5) × 60 ⇒ 0.6 (x/m) = (0.6/2) ⇒ 0.3

Q. $100 m L$ of $0.6 M$ acetic acid is shaken with $2 g$ activated carbon. The final concentration of the solution after adsorption is $0.5 M$ . What is the amount of acetic acid adsorbed per gram of carbon?

Mass of acetic acid adsorbed by $2 g$ charcoal
$= 100 \times 1 0^{- 3} \times (0.6 - 0.5) \times 60$
$\Rightarrow 0.6$
$\frac{x}{m} = \frac{0.6}{2}$
$\Rightarrow 0.3$

Q. 100mL of 0.6M acetic acid is shaken with 2g activated carbon. The final concentration of the solution after adsorption is 0.5M. What is the amount of acetic acid adsorbed per gram of carbon?

Mass of acetic acid adsorbed by 2g charcoal =100×10−3×(0.6−0.5)×60 ⇒0.6 mx​=20.6​ ⇒0.3

Q. $100 m L$ of $0.6 M$ acetic acid is shaken with $2 g$ activated carbon. The final concentration of the solution after adsorption is $0.5 M$ . What is the amount of acetic acid adsorbed per gram of carbon?

Mass of acetic acid adsorbed by $2 g$ charcoal
$= 100 \times 1 0^{- 3} \times (0.6 - 0.5) \times 60$
$\Rightarrow 0.6$
$\frac{x}{m} = \frac{0.6}{2}$
$\Rightarrow 0.3$