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Tardigrade
Question
Chemistry
100 mL of 0.1 N NaOH solution is required for neutralisation of 0.49 g of a dibasic acid. What is the molecular weight of the acid?
Q.
100
m
L
of
0.1
N
N
a
O
H
solution is required for neutralisation of
0.49
g
of a dibasic acid. What is the molecular weight of the acid?
1723
224
Some Basic Concepts of Chemistry
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A
49
29%
B
98
36%
C
490
24%
D
196
11%
Solution:
Milliequivalents of acid = Milliequivalents of base
E
0.49
×
1000
=
0.1
×
100
(Say equivalent wt. of acid
=
E
)
∴
E
=
49
Molecular weight = Equivalent weight
×
Basicity
=
49
×
2
=
98