100 mL of 0.1 M H2SO4 is mixed with 100 mL of 0.1 NaOH . The normality of the solution obtained is

Question

100 mL of 0.1 M H2SO4 is mixed with 100 mL of 0.1 NaOH . The normality of the solution obtained is (A)  0.4 N  (B)  0.05 N  (C)  0.04 N  (D)  0.2 N

Tardigrade Admin · Accepted Answer

N1V1 = 0.2 × 100 = 20 (0.1 MH2SO4 = 0.2 NH2 SO4) acid N2V2 = 0.1 × 100 = 10 (base) N1V1 acid > N2V2 base hence, resultant mixture is acidic. Resultant normality = (N1V1 - N2V2/V1 + V2) = (20-10/200) = (10/200) = 0.05 N

Q. $100 m L$ of $0.1 M H_{2} S O_{4}$ is mixed with $100 m L$ of $0.1 N a O H$ . The normality of the solution obtained is

$0.4 N$

$0.05 N$

$0.04 N$

$0.2 N$

Q. 100mL of 0.1MH2​SO4​ is mixed with 100mL of 0.1NaOH . The normality of the solution obtained is

0.4N

0.05N

0.04N

0.2N

N1​V1​=0.2×100=20 (0.1MH2​SO4​=0.2NH2​SO4​) acid N2​V2​=0.1×100=10 (base) N1​V1​ acid >N2​V2​ base hence, resultant mixture is acidic. Resultant normality =V1​+V2​N1​V1​−N2​V2​​=20020−10​ =20010​=0.05N

Q. $100 m L$ of $0.1 M H_{2} S O_{4}$ is mixed with $100 m L$ of $0.1 N a O H$ . The normality of the solution obtained is

$0.4 N$

$0.05 N$

$0.04 N$

$0.2 N$