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Chemistry
100 mL of 0.1 M H2SO4 is mixed with 100 mL of 0.1 NaOH . The normality of the solution obtained is
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Q. $ 100\, mL $ of $ 0.1 \,M \,H_2SO_4 $ is mixed with $ 100 \,mL $ of $ 0.1 \,NaOH $ . The normality of the solution obtained is
AMU
AMU 2013
Some Basic Concepts of Chemistry
A
$ 0.4\,N $
29%
B
$ 0.05\,N $
53%
C
$ 0.04\,N $
6%
D
$ 0.2\,N $
12%
Solution:
$N_1V_1 = 0.2 \times 100 = 20$
$(0.1\,MH_2SO_4 = 0.2 \,NH_2 SO_4)$ acid
$N_2V_2 = 0.1 \times 100 = 10 $ (base)
$N_1V_1 $ acid $ > N_2V_2$ base hence, resultant mixture is acidic.
Resultant normality
$ = \frac{N_1V_1 - N_2V_2}{V_1 + V_2} = \frac{20-10}{200}$
$ = \frac{10}{200} = 0.05 \,N$