100 g of CaCO3 is treated with 1 litre of 1 N HCl. What would be the weight of CO2 liberated after the completion of the reaction ?

Question

100 g of CaCO3 is treated with 1 litre of 1 N HCl. What would be the weight of CO2 liberated after the completion of the reaction ? (A) 5.5 g (B) 11 g (C) 22 g (D) 33 g

Tardigrade Admin · Accepted Answer

1 L of 1N HCl = 1 L of 1 M HCl = 1 mol of HC1 Amount of CaCO3 = 100 g = 1 mol underset1 molCaCO3 + underset 2 mol2 HCl → CaCl2 + underset 44 g(1 mol)CO2 + H2O Thus HCl is the limiting reactant. 2 mol of HCl after reaction with CaCO3 give CO2= 1 mol 1 mol of HCl after reaction with CaCO3 give CO2 = mol. ∴ Mass of CO2 obtained = 1/2 × 44 = 22 g

Q. 100g of CaCO3​ is treated with 1 litre of 1NHCl. What would be the weight of CO2​ liberated after the completion of the reaction ?

5.5 g

11 g

22 g

33 g

Q. $100 g$ of $C a C O_{3}$ is treated with 1 litre of $1 N H Cl$ . What would be the weight of $C O_{2}$ liberated after the completion of the reaction ?