100 cells each of emf 5 volt and internal resistance 1 ohm are to be arranged so as to produce maximum current in a 25 ohm resistance. Each row is to contain equal numbers of cells. The number of rows should be

Question

100 cells each of emf 5 volt and internal resistance 1 ohm are to be arranged so as to produce maximum current in a 25 ohm resistance. Each row is to contain equal numbers of cells. The number of rows should be (A) 2 (B) 4 (C) 5 (D) 10

Tardigrade Admin · Accepted Answer

Let m be the number of rows
Let n be the number of cells in a row
Then

m \times n = 100

...(i)
Also condition of maximum current is

R = \frac{n r}{m}

(ii)

25 = \frac{1 \times n}{m}

\Rightarrow n = 25 m

...(ii)
On solving (i) and (ii), we get

m = 2

Q. 100 cells each of emf 5 volt and internal resistance 1 ohm are to be arranged so as to produce maximum current in a 25 ohm resistance. Each row is to contain equal numbers of cells. The number of rows should be

2

4

5

10

Let m be the number of rows Let n be the number of cells in a row Then m×n=100 ...(i) Also condition of maximum current is R=mnr​ (ii) 25=m1×n​ ⇒n=25m...(ii) On solving (i) and (ii), we get m=2

Q. $100$ cells each of emf $5$ volt and internal resistance $1$ ohm are to be arranged so as to produce maximum current in a $25$ ohm resistance. Each row is to contain equal numbers of cells. The number of rows should be

Let m be the number of rows
Let n be the number of cells in a row
Then $m \times n = 100$ ...(i)
Also condition of maximum current is
$R = \frac{n r}{m}$
(ii) $25 = \frac{1 \times n}{m}$
$\Rightarrow n = 25 m$ ...(ii)
On solving (i) and (ii), we get
$m = 2$