10 moles of an ideal monoatomic gas at 10° C is mixed with 20 moles of another monoatomic gas at 20° C . Then the temperature of the mixture is

Question

10 moles of an ideal monoatomic gas at 10° C is mixed with 20 moles of another monoatomic gas at 20° C . Then the temperature of the mixture is (A)  15.5° C  (B)  15° C  (C)  16° C  (D)  16.6° C

Tardigrade Admin · Accepted Answer

Temperature of the mixture is given by T=(n1 m1+n2 m2/n1+n2) T=(10 × 10+20 × 20/10+20) =(500/30) ≈ 16.6° C

Q. $10$ moles of an ideal monoatomic gas at $1 0^{\circ} C$ is mixed with $20$ moles of another monoatomic gas at $2 0^{\circ} C$ . Then the temperature of the mixture is

$15. 5^{\circ} C$

$1 5^{\circ} C$

$1 6^{\circ} C$

$16. 6^{\circ} C$

Temperature of the mixture is given by
$T = \frac{n _{1} m _{1} + n _{2} m _{2}}{n _{1} + n _{2}}$
$T = \frac{10 \times 10 + 20 \times 20}{10 + 20}$
$= \frac{500}{30} \approx 16. 6^{\circ} C$

Q. 10 moles of an ideal monoatomic gas at 10∘C is mixed with 20 moles of another monoatomic gas at 20∘C . Then the temperature of the mixture is

15.5∘C

15∘C

16∘C

16.6∘C