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Tardigrade
Question
Mathematics
(1 - tan2 (45°-A) /1 + tan2(45°-A)) is equal to
Q.
1
+
t
a
n
2
(
4
5
∘
−
A
)
1
−
t
a
n
2
(
4
5
∘
−
A
)
is equal to
1679
214
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A
sin 2A
B
cos 2A
C
tan 2 A
D
cot 2A.
Solution:
Correct answer is (a) sin 2A