Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
1 mole of NH 3 gas at 27° C is expanded in reversible adiabatic condition to make volume 8 times (γ=1.33). Final temperature and work done respectively are :
Q.
1
mole of
N
H
3
gas at
2
7
∘
C
is expanded in reversible adiabatic condition to make volume
8
times
(
γ
=
1.33
)
. Final temperature and work done respectively are :
1862
214
Report Error
A
150 K , 900 cal
80%
B
150 K , 400 cal
4%
C
250 K , 1000 cal
16%
D
200 K , 800 cal
0%
Solution:
T
1
V
1
γ
−
1
=
T
2
V
2
γ
−
1
⇒
300
×
V
1/3
=
T
2
(
8
V
)
1/3
⇒
T
2
=
150
K
W
=
n
C
v
(
T
2
−
T
1
)
=
1
×
3
R
(
150
−
300
)
=
3
×
2
(
−
150
)
=
−
900
c
a