1 mole of NaCl is doped with 10−5 mole of SrCl2. The number of cationic vacancies in the crystal lattice will be

Question

1 mole of NaCl is doped with 10−5 mole of SrCl2. The number of cationic vacancies in the crystal lattice will be (A) 6.022 x 1023 (B) 12.044 x 1020 (C) 6.022 x 1018 (D) 6.022 × 1015

Tardigrade Admin · Accepted Answer

1 mol SrCl2 gives 1 cationic vacancy. 10-5 moles of SrCl2 gives 10-5 mole cationic vacancies. ∴ The number of cationic vacancy in 1 moles of NaCl when it is doped with 10-5 moles of srcl2 is 6.022×1018.

Q. 1 mole of NaCl is doped with 10⁻⁵ mole of SrCl₂. The number of cationic vacancies in the crystal lattice will be

6.022 x 10²³

12.044 x 10²⁰

6.022 x 10¹⁸

6.022 × 10¹⁵

1 mol $S r C l_{2}$ gives 1 cationic vacancy.
$1 0^{- 5}$ moles of $S r C l_{2}$ gives $1 0^{- 5}$ mole cationic vacancies.
$∴$ The number of cationic vacancy in 1 moles of NaCl when it is doped with $1 0^{- 5} m o l es o f src l_{2} i s 6.022 \times 1 0^{18} .$

Q. 1 mole of NaCl is doped with 10−5 mole of SrCl2. The number of cationic vacancies in the crystal lattice will be

6.022 x 1023

12.044 x 1020

6.022 x 1018

6.022 × 1015