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  4. 1 mole of NaCl is doped with 10−5 mole of SrCl2. The number of cationic vacancies in the crystal lattice will be

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Q. 1 mole of NaCl is doped with 10−5 mole of SrCl2. The number of cationic vacancies in the crystal lattice will be

KCETKCET 2019The Solid State

Solution:

1 mol $SrCl_{2}$ gives 1 cationic vacancy.
$10^{-5}$ moles of $SrCl_{2}$ gives $10^{-5}$ mole cationic vacancies.
$\therefore \,$ The number of cationic vacancy in 1 moles of NaCl when it is doped with $10^{-5} \, moles\, of \, srcl_{2} \, is\, 6.022\times10^{18}.$