1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27° C. The work done is 3 kJ mol -1. The final temperature of the gas is K (Nearest integer). Given C V =20 J mol -1 K -1

Question

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27° C. The work done is 3 kJ mol -1. The final temperature of the gas is K (Nearest integer). Given C V =20 J mol -1 K -1 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

q =0 Δ U = w 1 × 20 ×[ T 2-300]=-3000 T 2-300=-150 T 2=150 K

Q. 1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of $2 7^{\circ} C$ . The work done is $3 k J m o l^{- 1}$ . The final temperature of the gas is _______ $K$ (Nearest integer). Given $C_{V} = 20 J m o l^{- 1} K^{- 1}$

$q = 0$
$Δ U = w$
$1 \times 20 \times [T_{2} - 300] = - 3000$
$T_{2} - 300 = - 150$
$T_{2} = 150 K$

Q. 1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27∘C. The work done is 3kJmol−1. The final temperature of the gas is _______ K (Nearest integer). Given CV​=20Jmol−1K−1

q=0 ΔU=w 1×20×[T2​−300]=−3000 T2​−300=−150 T2​=150K

Q. 1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of $2 7^{\circ} C$ . The work done is $3 k J m o l^{- 1}$ . The final temperature of the gas is _______ $K$ (Nearest integer). Given $C_{V} = 20 J m o l^{- 1} K^{- 1}$

$q = 0$
$Δ U = w$
$1 \times 20 \times [T_{2} - 300] = - 3000$
$T_{2} - 300 = - 150$
$T_{2} = 150 K$