1 mole of equimolar mixture of ( Fe )2((( C )2( O )4))3 and FeC 2 O 4 requires X moles of KMnO 4 in acid medium for complete reaciton. The value of X is:

Question

1 mole of equimolar mixture of ( Fe )2((( C )2( O )4))3 and FeC 2 O 4 requires X moles of KMnO 4 in acid medium for complete reaciton. The value of X is: (A) 0.9 (B) 0.6 (C) 1.2 (D) 0.8

Tardigrade Admin · Accepted Answer

mathrmFe2( mathrmC2 mathrmO4)3 longrightarrow 2 mathrmFe3++6 mathrmCO2+6 mathrme ( n Factor =6) mathrmFe( mathrmC2 mathrmO4) longrightarrow mathrmFe3++2 mathrmCO2+3 mathrme ( n Factor =3) Meqs of [ mathrmFe2( mathrmC2 mathrmO4)3+ mathrmFe( mathrmC2 mathrmO4)]=0.5 × 6+0.5 × 3 =4.5 text Eqs. =4.5 text Eqs. of mathrmKMnO4 =(4.5/5)=0.9 text moles of mathrmKMnO4

Q. 1 mole of equimolar mixture of (Fe)2​(((C)2​(O)4​))3​ and FeC2​O4​ requires X moles of KMnO4​ in acid medium for complete reaciton. The value of X is:

0.9

0.6

1.2

0.8

Fe2​(C2​O4​)3​⟶2Fe3++6CO2​+6e( n Factor =6) Fe(C2​O4​)⟶Fe3++2CO2​+3e( n Factor =3) Meqs of [Fe2​(C2​O4​)3​+Fe(C2​O4​)]=0.5×6+0.5×3 =4.5 Eqs. =4.5 Eqs. of KMnO4​ =54.5​=0.9 moles of KMnO4​

Q. 1 mole of equimolar mixture of $(F e)_{2} (((C)_{2} (O)_{4}))_{3}$ and $F e C_{2} O_{4}$ requires $X$ moles of $K M n O_{4}$ in acid medium for complete reaciton. The value of $X$ is: