1 mole of an ideal gas expands isothermally at 27° C from 2 L volume to 20 L. The maximum work done in the process is

Question

1 mole of an ideal gas expands isothermally at 27° C from 2 L volume to 20 L. The maximum work done in the process is (A) -690.9 R (B) 690.9 R (C) -345.2 R (D) 345.2 R

Tardigrade Admin · Accepted Answer

For reversible isothermal expansion w =-2.303 nRT log ( V f / V i ) =-2.303 × 1 × R × 300 log (20/2) =-690.9 R

Q. $1 m o l e$ of an ideal gas expands isothermally at $2 7^{\circ} C$ from $2 L$ volume to $20 L$ . The maximum work done in the process is

-690.9 R

690.9 R

-345.2 R

345.2 R

For reversible isothermal expansion
$w = - 2.303 n RT lo g \frac{V _{f}}{V _{i}}$
$= - 2.303 \times 1 \times R \times 300 lo g \frac{20}{2}$
$= - 690.9 R$

Q. 1mole of an ideal gas expands isothermally at 27∘C from 2L volume to 20L. The maximum work done in the process is