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Q. $1 \,mole$ of an ideal gas expands isothermally at $27^{\circ} C$ from $2\, L$ volume to $20 \,L$. The maximum work done in the process is

Solution:

For reversible isothermal expansion
$w =-2.303\, nRT \,\log \frac{ V _{ f }}{ V _{ i }} $
$=-2.303 \times 1 \times R \times 300 \log \frac{20}{2} $
$=-690.9\, R$