1 gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2. The molar mass of M2CO3 in g mol-1 is :

Question

1 gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2. The molar mass of M2CO3 in g mol-1 is : (A) 118.6 (B) 11.86 (C) 1186 (D) 84.3

Tardigrade Admin · Accepted Answer

M 2 CO 3+2 HCl arrow 2 MCl + H 2 O + CO 2 n M 2 CO 3= n CO 2 (1/ M M 2 CO 3) =0.01186 M M 2 CO 3 =(1/0.01186) = 84.3 g / mol

Q. 1 gram of a carbonate $(M_{2} C O_{3})$ on treatment with excess $H Cl$ produces $0.01186$ mole of $C O_{2}$ . The molar mass of $M_{2} C O_{3}$ in g $m o l^{- 1}$ is :

$118.6$

$11.86$

$1186$

$84.3$

$M_{2} C O_{3} + 2 H Cl \to 2 MCl + H_{2} O + C O_{2}$

$n_{M_{2} C O_{3}} = n_{C O_{2}}$

$\frac{1}{M _{M_{2} C O_{3}}} = 0.01186$

$M_{M_{2} C O_{3}} = \frac{1}{0.01186}$

$= 84.3 g / m o l$

Q. 1 gram of a carbonate (M2​CO3​) on treatment with excess HCl produces 0.01186 mole of CO2​. The molar mass of M2​CO3​ in g mol−1 is :

118.6

11.86

1186

84.3