1 g of a steam at 100° C melt how much ice at 0° C ? (Latent heat of ice =80 cal / gm and latent heat of steam =540 cal / gm )

Question

1 g of a steam at 100° C melt how much ice at 0° C ? (Latent heat of ice =80 cal / gm and latent heat of steam =540 cal / gm ) (A) 1 gm (B) 2 gm (C) 4 gm (D) 8 gm

Tardigrade Admin · Accepted Answer

Suppose m gm ice melted, then heat required for its melting =m L=m × 80 cal. Heat available with steam for being condensed and then brought to 0° C. =1 × 540+1 × 1 ×(100-0)=640 cal ⇒ Heat lost = Heat taken ⇒ 640=m × 80 ⇒ m=8 gm

Q. 1g of a steam at 100∘C melt how much ice at 0∘C? (Latent heat of ice =80cal/gm and latent heat of steam =540cal/gm )

1 gm

2 gm

4 gm

8 gm

Suppose mgm ice melted, then heat required for its melting =mL=m×80 cal. Heat available with steam for being condensed and then brought to 0∘C. =1×540+1×1×(100−0)=640cal ⇒ Heat lost = Heat taken ⇒640=m×80⇒m=8gm

Q. $1 g$ of a steam at $10 0^{\circ} C$ melt how much ice at $0^{\circ} C ?$ (Latent heat of ice $= 80 c a l / g m$ and latent heat of steam $= 540 c a l / g m$ )