Question

$1g{H}_2$ gas $STP$ is expanded so that the volume is doubled. Hence, work done is

• A. 22.4 L-atm
• B. 5.6 L-atm
• C. 11.2 L-atm
• D. 44.8 L-atm

Answer 1

Answer: (C)

$V_1$ (volume of $1g{H}_2)=11.2L$ at STP
$V_2($ volume of $1g{H}_2)=22.4L$
$\therefore W=P\Delta V=11.2L$ atm