Question

Statement I Boron always forms covalent bond.
Statement II The small size of $B^{3+}$ favours formation of covalent bond.
(1) Statement I is correct Statement II is correct Statement II is the correct explanation of Statement I
(2) Statement I is correct; Statement II is correct Statement II is not the correct explanation of Statement I
(3) Statement I is correct: Statement II is incorrect
(4) Statement I is incorrect; Statement II is correct

Answer 1

Small size and high charge on $B^{3+}$ makes it highly polarising. Therefore, in most of its compounds, boron forms covalent bonds.
Hence, both statement I and statement II are correct and statement II is a correct explanation of statement I.