Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
(1/4.5)+(1/5.6)+(1/6.7)+....+(1/(n+3)(n+4))
Q.
4.5
1
+
5.6
1
+
6.7
1
+
....
+
(
n
+
3
)
(
n
+
4
)
1
2052
215
Principle of Mathematical Induction
Report Error
A
n
+
4
n
16%
B
4
(
n
+
4
)
n
38%
C
4
(
n
+
4
)
n
(
n
+
1
)
29%
D
4
(
n
+
3
)
n
17%
Solution:
Put n = 2.
S
2
=
4.5
1
+
5.6
1
=
12
1
option (2) =
4
(
2
+
4
)
2
=
12
1