Question

1.22 g C₆H₅COOH is added into the 100 g solvent CH₃COCH₃ where data of Δ T_b and K_b are given as:

ΔT_b = 0.17, solute by K_b = 1.7 K kg/mol

Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.

Answer 1

Answer: 122

$\Delta {\text{T}}_{\text{b}}=\text{0.17}={\text{K}}_{\text{b}}\cdot \text{m}$

$\text{0.17}=\text{1.7}\times \frac{\text{1.22/M}}{\text{100/1000}}$

M = 122 g/mole

Benzoic acid is not associated or dissociated.